Physics 4D HomeWork Even Problems Answers
Chapter 12)proof
4)t(ud)=0.4167 hr, t(c) = 0.4082 hr
10)a)8.33 x 10^-8 s b)24 m
12)a)70 beats/min b)31 beats/min
14)proof
24)0.982C
26)0.95C
30)a)2d/(c+v) b)(2d/c)SQRT((c-v)/(c+v))
34)a)83.5 m, 62.5m b)20.3m, 27.1m c)1.67hr d)1.47hr e)1.97hr f)#2 lives, #1 dies
36)a)0.943C b)2550m
Chapter 2
2)a)0.85c b)no change
6)proof
8)a)939.4 MeV b)3.01 x 10^3 MeV c)2.07 x 10^3 MeV
10)0.75c
18)a)0.0035u b) 2.75 MeV
20) E = 0.783 MeV
22)a) p=206 MeV/c, u =0.827c b) m= 498 MeV/c^2
28)a)4.00 x 10^-14 kg b)1.60 x 10^-12
Chapter 3
4)4.62 x 10^6 W/m^2
20) 2.00 eV
22)1.35 eV
24)a)0.00243 nm b)74.4 eV
28)a)0.00775 nm b)87.2 or 92.8 c)35.9
30)0.0120 nm
32)a)1.95 x 10^-3 eV b)0.0861 nm
38) a)d1 = do/(2^1/2), d2 = do/(5^1/2) b)51.4, 57.8, 64.3
42) a)0.571 eV b)1.54 V
46)22.9
48)a)1.01 x 10^-10 m b)81.1
Chapter 4
14) a) 0.0529 nm,0.2121 nm, 0.4772 nm b)2.19 x 10^6 m/s, 1.09 x 10^6 m/s, 7.28 x 10^5 m/s c) no
18) a)12.1 eV b)12.1 eV, 10.2 eV, 1.89 eV
24)a)102.517 nm b) p =6.47 x 10^-27 kg m/s, K=7.83x10^-8 eV
26) max = 121.5 nm, min = 91.6 nm
28)5.385 keV
36)a),b)worked out in lecture c) frequency of photon should approach frequency of rotation
for large quantum numbers.
42)1.89x10^6 m/s
44)a)oxygen b)41 nm, 33.8 nm, 30.4 nm
Chapter 5
2)a)0.0173 nm b)0.00536 nm
4)7.28 x 10^6 m/s
6)1.28 x 10^-4 nm
16) Vg = (3/2)Vp
18)3.51 x 10^-32 m
24)Did in class
30)a) 1.07 x 10^-17 kg m/s b) 6.2 x 10^-17 m
32)a)4.34 x 10^14 Hz b)691 nm c)3.30 x 10^-10 eV
Chapter 6
2)a)(4/L)^(1/2) b)0.409
6)Did in class
12)7.93x10^-10m
16) a)0.1955 b)0.3319 c)YES!!!
18)check graphically
24) a)alpha = mw/2h, E=(3/2)hf b)C = (32*alpha^3/Pi)^0.25
26)P(x)=1/(Pi*(A^2-x^2)^0.5)
28)a) did in class b)<x>=L/2, <x^2>=L^2/3
30)proof
32)<x>=0, <x^2>=h/(4Pimw), DeltaX = [h/(4Pimw)]^0.5
34)h/(4Pi)
Chapter 7
2)proof
4) 1.8x10^-4 mA
Chapter 8
4)a)results are similar to the 3D problem with the exception that you only have two component for the wavefunction.
6)Solve the TISE to find the wavefunction!!! The energy will be sharp. That is, you know the value of E exactly!!
10)a)3.65x10^-34 Js b)3.16x10^-34Js
12) a)& b) did in class c)graph d)proof e)0.496
18)a)6 b)-0.378 eV c)4.47 h/2Pi d)m = -4,-3,-2,-1,0,1,2,3,4; see example in class
22)5ao
24)=-27.2 eV, <k>=13.6 eV
26)0.176, 0.371
30)0.866h/2Pi
Handout
9) a)c-v b)c +v c)(c^2-v^2)^0.5
10) 300 m/s,360 m/s, 329 m/s
11) a) (u^2-v^2sin^2 (Theta)-vcos(theta))^0.5
b) max = u+v, min = u-v
c) 5%